10. A 5.0 g pellet is placed in the barrel of a toy gun and is propelled by a spring of force
constant 50. N/m. The spring is compressed 20. cm and then released. Calculate the
maximum velocity of the pellet when shot horizontally.

v = 20m/s

Explanation:

m = 5g = 0.005kg

k = 50 N/m

e = 20cm = 0.20 m

Ek = Eep

1/2 mv² = 1/2 ke²

mv² = ke²

v² = ke²/m

v = √(ke²/m)

v = √400

v = 20m/s

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.