An infinite line of positive charge lies along the y axis, with charge density λ = 1.70 μC/m. A dipole is placed with its center along the x axis at x = 26.0 cm. The dipole consists of two charges ±10.0 μC separated by 2.00 cm. The axis of the dipole makes an angle of 30.0° with the x axis, and the positive charge is farther from the line of charge than the negative charge. Find the net force exerted on the dipole.

the force exerted on the dipole = 0.11 N

Explanation:

Using F = (KQq/r^2) sin ∅

the distance of dipole to the line charge will be 30 cm, hence 1 st charge on the dipole -10 micro C is 29 cm and that to + 10 micro C is 31 cm (2 cm apart).

0.91 N with -ve charge and 0.80 to +ve charge. The difference is the force on the dipole i.e 0.11 N

momentum of soft ball three times less than baskey ball

b. false

explanation:

suppose a rock in free fall is dropped off a cliff. after falling for 5 seconds, its speed would not be 100 m/s.