Physics, 19.02.2020 04:57 smmailloux2335
A man stands on a platform that is rotating at 3.8 rpm; his arms are outstretched and he holds a brick in each hand. The rotational inertia of the system consisting of the man, bricks, and platform about the central axis of the platform is 4.65 kg-m². By moving the bricks the man decreases the rotational inertia of the system to 3.4 kg-m².
(a) what is the resulting angular speed of the platform and
(b) what is the ratio of the new kinetic energy of the system to the original kinetic energy?
Answers: 2
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A man stands on a platform that is rotating at 3.8 rpm; his arms are outstretched and he holds a bri...
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