A bus leaves New York City, takes a non-direct route and arrives in St. Louis, Missouri 23 hours, 16 minutes later. If the distance between the two cities is 1250 km, what is the magnitude of the bus' average velocity?

vavg = 53.7 km/h

Explanation:

In order to find the magnitude of the bus'average velocity, we need just to apply the definition of average velocity, as follows:

where xf - xo = total displacement = 1250 Km

If we choose t₀ = 0, ⇒ t = 23h 16'= 23h + 0.27 h = 23.27 h

⇒

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