A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 50.0 m above ground level, and the ball is fired with initial horizontal speed v0. Assume acceleration due to gravity to be g = 9.80 m/s2. What is the y position of the cannonball when it is at distance D/2 from the hill? If you need to, you can use the trajectory equation for this projectile, which gives y in terms of x directly: y=H−gx22v20x. You should already know v0x from the previous part.