A 20 μF capacitor has previously been charged up to contain a total charge of Q=100 μC on it. The capacitor is then discharged by connecting it directly across a 100kΩ resistor. Calculate the charge remaining on the capacitor exactly 3.00 seconds after being connected to the resistor.

Q= 22.3 μC

Explanation:

Given that

C= 20 μF

Qo= 100 μC

R= 100 kΩ

t= 3 s

T= R C

T= 100 x 1000 x 20 x 10⁻⁶ s

T=2 s

We know that charge on the capacitor is given as

Q= 0.0000223 C

Q= 22.3 μC

increases it

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.