A 2.7 kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0-m-high cliff. At the instant the ball is thrown, a woman starts running away from the base of the cliff with a constant speed of 6.00 m/s. The woman runs in a straight line on level ground. Ignore air resistance on the ball.

(a) At what angle above the horizontal should the ball be thrown so that the runner will catch it  just before it hits the ground? (b) How far does the woman run before she catches the ball?

(a) = 72.54°

   ≅ 72.5°

(b) = 33.4 m

Explanation:

see the attached file below

you have to draw the persons position over there

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation: