A carbon resistor is to be used as a thermometer. On a winter day when the temperature is 4.00 ∘C∘C, the resistance of the carbon resistor is 217.4 ΩΩ . What is the temperature on a spring day when the resistance is 216.0 ΩΩ ?

16°C

The equation relating temperature with resistance is given as follows;

= [( - ) + 1]         --------------(i)

Where;

= Temperature at some reference point

= Resistance at the reference point

T = Temperature at some other point

= Resistance at the other point

= constant called "temperature coefficient of the resistor material"

From the question;

Let's take the reference point temperature () as 4.00°C;

Therefore;

= Resistance at the reference point = 217.4Ω

= Resistance at the other point = 216.0Ω

= Temperature coefficient of the resistor material (carbon) = -0.0005/°C

Now substitute these values into equation (i) as follows;

216.0 = 217.4 [(-0.0005)( - 4) + 1]

216.0 = 217.4 [-0.0005 + 0.002 + 1]

216.0 = 217.4 [-0.0005 + 1.002]

Divide through by 217.4 as follows;

0.994 = 1.002 - 0.0005T

Solve for T;

0.0005T = 1.002 - 0.994

0.0005T = 0.008

T = 0.008 / 0.0005

T = 16°C

Therefore, the temperature on a spring day at that resistance is 16°C

answer; how far out of place which the object finished relative to the starting location;

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min