It is weigh-in time for the local under-85-kg rugby team. The bathroom scale used to assess eligibility can be described by Hooke’s law and is depressed 0.75 cm by its maximum load of 120 kg. (a) What is the spring’s effective spring constant? (b) A player stands on the scales and depresses it by 0.48 cm. Is he

Explanation:

Depression = .75 x 10⁻² m

Load = 120 g

Spring constant = 120g / .75 x 10⁻²

= 160 x 10² g / m

b )

Depression by player

= .48 x 10⁻² m

His weight

= .48 x 10⁻² x 160 x 10² g

= 76.8 kg

So he is eligible.

the answer would be c. motion and direction

i hope this : )

explanation:

the masses of the objects and the distance between them