A doubly ionized molecule (i. e., a molecule lacking two electrons) moving in a magnetic field experiences a magnetic force of 5.75 × 10 − 16 N 5.75×10−16 N as it moves at 385 m/s 385 m/s at 63.9 ∘ 63.9∘ to the direction of the field. Find the magnitude of the magnetic field.

Explanation:

The given data is as follows.

           F =

          q =

          v = 385 m/s

        = 0.876

Now, we will calculate the magnitude of magnetic field as follows.

              B =

                  =

                  = T

                  = 10.65 T

Thus, we can conclude that magnitude of the magnetic field is 10.65 T.

answer: electrons

do you have a formula possibly