The tires of a car support the weight of a stationary car. If one tire has a slow leak, the air pressure within the tire will with time, the surface area between the tire and the road will with time, and the net force the tire exerts on the road will with time. a) Increase, Increase, Increase
b) Decrease, decrease, decrease
c) Decrease. increase, increase
d) Decrease, increase, remain constant
e) Decrease, increase, decrease

The answer is E. Decrease, increase, decrease

Explanation:

The pressure within the tire wall is a result of the molecules of air colliding with the walls of the tire, if there is a leakage that means some or all of the air molecules will escape resulting in a decrease in the collision between the molecules and the tire wall which means the pressure decreases within the walls which also translates to a decrease in pressure exerted by the tire on the ground surface.

Before the leakage, the tire walls are kept tensed due to the internal pressure exerted by the air molecules. When the leakage occurs the air molecules escape and this makes the tire loose its firm upright shape thereby falling to the floor and creating an increase in the area of contact between the tire and the floor surface.

The force exerted on the floor by the tire is proportional to the the pressure exerted and the surface area through which this force is applied, though the pressure is seen to decrease and the surface area seen to increase, one must consider the weight loss due to the air molecules that escapes which causes the force to decrease.

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