A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800 km. The speed of the satellite is (ME = 5.98 × 1024 kg, RE = 6.37 × 106 m, G = 6.67 × 10−11 N·m2/kg2)

Explanation:

The given data is as follows.

            m = 5000 kg,            h = 800 km =

    ,    r = R + h =

    kg,   G =

As we know that,

                      v =

And, it is known that formula to calculate angular velocity is as follows.

                            v =

                               =

                                =

Thus, we can conclude that speed of the satellite is .

0.863333

86%

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