A mail carrier leaves the post office and drives 2.00 km to the north. He then drives in a direction 60.0° south of east for 7.00 km. After dropping off a package, he drives 9.50 km 35.0° north of east to Starbucks. What is his distance from the starting point? (Hint: draw a picture) (3 sig figs) *

12.97 km

Explanation:

In order to find the resultant displacement, we have to resolve each of the 3 displacements along the x and y direction.

Taking north as positive y direction and east as positive x-direction, we have:

- Displacement 1: 2.00 km to the north

So

- Displacement 2: 60.0° south of east for 7.00 km

So

- Displacement 3: 9.50 km 35.0° north of east

So

So the net displacement along the two directions is:

So, the  distance between the initial and final position is equal to the magnitude of the net displacement:

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)