You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abort the landing, so he pulls up, moving in a semicircular upward-bending path. The path has a radius of 490 mm with a radial acceleration of 18 m/s2m/s2.?

Speed of the plane will be equal to 2.969 m/sec

Explanation:

Note - It is not given but we have to find the speed of the plane.

We have given radius r =

Angular acceleration

We have to fond the speed of the plane

We know that angular acceleration is equal to

So

v = 2.969 m/sec

So speed of the plane will be equal to 2.969 m/sec

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s