An electric heater carries a current of 17.5 A when operating at a voltage of 120 V. What is the resistance of the heater?

16Ω

According to Ohm's law, the voltage (V) passing across a device is related to the current (I) flowing through it as follows;

V = I x R          -------------------(i)

Where;

R = the resistance of the device

According to the question, the device is the heater and it has the following details;

V = operating voltage = 120V

I = current = 17.5A

Now, substitute these values into equation(i) as follows;

120 = 17.5 x R

Solve for R;

R =

R = 16Ω

Therefore, the resistance of the heater is 16Ω

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation:

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz