A 6.7 kg block is released from rest on a frictionless inclined plane making an angle of 25.7° with the horizontal. Calculate the time it will take this block when released from rest to travel a distance of 0.5 m along the ramp.

So time taken by block to travel 0.5 m from rest will be 0.4853 sec

Explanation:

We have given mass of the block m = 6.7 kg

angle of inclination

Distance traveled s = 0.5 m

Initial velocity u = 0 m/sec

Acceleration of the block

From second equation of motion we know that

So

t = 0.4853 sec

So time taken by block to travel 0.5 m from rest will be 0.4853 sec

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

thermal energy is the answer