A flowerpot falls off a windowsill and falls past the window below. You may ignore air resistance. It takes the pot 0.380 ss to pass from the top to the bottom of this window, which is 2.00 mm high.
How far is the top of the window below the windowsill from which the flowerpot fell?

The top of the window is 0.5 m below the sill of the upper window  

Explanation:

We have the time the pot takes to fall a distance y- yo = 2.0 m and g = 9.8, from this we can calculate the velocity of the pot when it just reached the top of the window in question. Take the positive y direction to be downward  

y-yo=vo*t+I/2gt^2

  vo=(y-yo-I/2gt^2)/t

  vo=3.138 m/s

The flowerpot falls from rest and we have the velocity it gains until it reaches the top of the window below, from this information we can get the distance between the sill and the top of the window below.  

v^2=vo^2+2g(y-yo)

y-yo=(v^2-vo^2)/2g

      = 0.5 m

The top of the window is 0.5 m below the sill of the upper window  

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

the correct choice is a .

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