A 11.0 µF capacitor is charged to 100 V and is then connected across a 470 Ω resistor only. What is the voltage accross the capacitor after 8.00 ms?

The voltage across the capacitor after 8.00 ms is 35.375 V.

Explanation:

Given that,

Capacitor = 11.0 μF

Voltage = 100 V

Resistance = 470 Ω

Time = 8.00 ms

We need to calculate the current

Using formula of current

Put the value into the formula

We need to calculate the voltage

Using ohm's law

We need to calculate the voltage across the capacitor after 8.00 ms

Using formula of voltage

Hence, The voltage across the capacitor after 8.00 ms is 35.375 V.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

answer; how far out of place which the object finished relative to the starting location;