During a crash test, two identical cars crash into two different barriers. Both cars are initially traveling at the same constant velocity. Car A crashes into a solid brick wall and decelerates to v = 0.0m/s over a distance dA = 10.0cm. Car B crashes into a row of shrubs and decelerates to v = 0.0m/s over a distance dB = 10.0m. During the collision Car A experiences an average force FA and Car B experiences and average force FB. What is the ratio FA/FB?

FA / FB = 100

Explanation:

given two identical cars

let their initial speed be U m/s

for car 1 let it deaccelerates with a1

0 = U² - 2*a1*(10cm)

a1 = U² / (2*(0.1))

car2 deaccelerates with a2

0 = U² - 2*a2*(10)

a2 = U² / (2*(10))

FA = m*a1  

FB = m*a2

FA/FB = a1 / a2

= 10/0.1

= 100

FA/FB = 100

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force