Light of wavelength 610 nm is incident on a slit of width 0.20 mm, and a diffraction pattern is produced on a screen that is 1.5 m from the slit. What is the distance of the second dark fringe from the center of the bright fringe>?

distance of the second dark fringe from the center of the bright fringe is 0.92 cm

Explanation:

given data

wavelength = 610 nm = 610 × m

slit of width = 0.20 mm = 0.20 × m

distance between screen and slit = 1.5 m

solution

we apply here formula for second minima that is

L =   ...................1

and here for second minima n is 2

put here value we get

L =    

L = 0.915 × m

so distance of the second dark fringe from the center of the bright fringe is 0.92 cm

i dont have a visual in front of me, but i can you reason to try to get the right one. the graph should look like this, 0 to 6 there is a spike, 12 to 14 there should be a very low point. slight increase in the graph at 12 to 14, and flat 14 to 18

explanation: