A stubborn, 120 kg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around the mule and pulls with his maximum force of 800 N. The coefficients of friction between the mule and the ground are μs=0.8 and μk=0.5. Is the farmer able to move the mule?

No

Explanation:

In order for the farmer to be able to put the mule in motion, the force he applies must be larger than the maximum value of the force of static friction exerted by the ground on the mule.

The maximum value of the force of static friction on the mule is given by:

where:

is the coefficient of static friction

m = 120 kg is the mass of the mule

is the acceleration due to gravity

Substituting, we find:

Here in this problem, the force applied by the farmer through the rope is

F = 800 N

We see that this force is smaller than the value of the maximum force of friction: therefore, the farmer will not be able to move the mule.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

when cloud cover increases then the suns ray's which provides the earth with light and warmth gets covered due to the due to the suns ray's being blocked, the temperature in that region

therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

happy to

pls mark as brainliest.