An object is placed at 4cm distance in front of a concave mirror of radius of curvature 24cm. find the position of image. is the image magnified? i want it with the graph digram

Radius of curvature, r = 2f

24 cm = 2f

2f = 24 

f = 24/2 = 12

Hence the focal length is = 12 cm.

Object distance, u = 4 cm.

Since the object is placed between the focus and the pole of the mirror, at this position for a concave mirror, the resulting image would be virtual and would be behind the mirror.

1/u - 1/v = 1/f

1/4 - 1/v = 1/12

1/4 - 1/12 = 1/v

1/v = 1/4 - 1/12 =   (3 - 1)/12 = 2/12 = 1/6

1/v = 1/6

v = 6

Therefore the image is 6cm behind the mirror. 

Magnification = v/u = 6/4 = 3/2 = 1.5

Yes, the image is magnified by 1.5 times.

Simply copy the diagram for an object placed between the focus and the pole of a mirror from your textbook.   

The best answer is (a) which is universal law is in effect at all times. it is constantly at play in everything we do and governs our lives. it is also important to note that universal law applies to not only everything on earth, but everything in the universe as well, which is another reason why it is in effect at all times.

If one were to put the y value into the equation, they could find out what x is for a certain value of y.  putting in the value of y (1), we get the equation: 1=4x-12=4xx=0.5this means that the value of x when why is 1 is x=0.5