Particle A has a charge of 33.5 nC, and particle B has a charge of −50.3 nC. The attractive force between them has a magnitude of 3.30 ✕ 10−4 N. How far apart are the particles?

Distance between both the charges will be equal to

Explanation:

We have first charge

And charge

Force between theses charges are equal to

We have to find the distance between two charges

According to coulomb's law force between two charges is equal to

So

So distance between both the charges will be equal to

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