The function f(x)equalsnegative 0.25 (x minus 2 )squared plus 8 models the path of a volleyball when the player is 2 feet from the net. The height of the net is 7 ft comma 4 in. Will the ball go over the net? What if the player moves back so she is 4 feet from the net? Explain.

The ball will go over the net when she's standing 2 feet away from the net, but not at 4 ft from the net

Explanation:

Suppose then when the player is 2ft from the net, we can plug in x = 2:

As 8 feet > 7 ft 4 in, the ball will go over the net

If the player moves back so that she's 4 feet from the net, plug in x = 4:

As 7 ft < 7 ft 4 in, this time the ball will NOT go over the net

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day