A projectile is shot from the edge of a cliff 170 m above ground with an initial speed of 75.0 m/s at an angle of 24° below the horizontal. How much time does it take the projectile to hit the ground?

It will take 6.1seconds for the projectile to hit the ground.

Explanation:

In projectile, the time taken by an object to spend in air is its time if flight.

Time of flight = 2Usin(theta)/g

where u is the initial velocity = 75m/s, theta = 24°, g = 10m/s²

Time of flight = 2(75)sin24°/10

Time of flight = 150sin24°/10

Time of fight = 6.1seconds.

This means that it will take 6.1seconds for the projectile to hit the ground.

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