A truck carrying a 65.4-kg crate accelerates from rest to [07] km/hr on a flat horizontal surface in 15.2 seconds. The acceleration was not constant. How much work (J) was done on the crate by the truck?

The work done on the crate by the truck is 9472.54 J.

Explanation:

Given that,

Mass of the truck, m = 65.4 kg

Initially, the object is at rest, u = 0

Final speed of the truck, v = 61.3 km /h = 17.02 m/s

m/s

Time, t = 15.2 s

We need to find the work done on the crate by the truck. The work done is equal to the change in kinetic energy of the truck as :

So, the work done on the crate by the truck is 9472.54 J. Hence, this is the required solution.

what is the question?

are there options? cause you ain’t. real specific