A satellite of mass =238 kg is in circular orbit around the Earth at an altitude above the earth's surface equal to the earth's mean radius (6370 km). At this distance, the free-fall acceleration is /4.What are (a) the speed and (b) the magnitude of the centripetal acceleration of the satellite?

Explanation:

a) the speed=

V=√2gr²/2r

=√gr/2

√10*637/2

V=31850m/s²

Magnitude of the acceleration

a=Gm/r²

10*238/(6370)²

2380/12740

=0.187

car a and b are moving in opposite directions

plz mark.me the brainliest i rlly need this kind of yours in exchange

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2