A gold wire has a 0.30 mm diameter cross section. Opposite ends of this wire are connected to the terminals of a 1.5 V battery. If the length of the wire is 5.5 cm, how much time, on average, is required for electrons leaving the negative terminal of the battery to reach the positive terminal? Assume the resistivity of gold is 2.44 10-8 Ω·m.

Answer :

The time is 0.46 sec.

Explanation:

Given that,

Diameter = 0.30 mm

Voltage = 1.5 V

Length = 5.5 cm

Resistivity of gold

We know that,

The resistance is

...(I)

The current is

...(II)

Put the value of R

We need to calculate the drift velocity

Using formula of drift velocity

Put the value into the formula

We need to calculate the time

Using formula of time

Put the value into the formula

Hence, The time is 0.46 sec.

the total distance traveled by the car is

30km + 49km = 79 km .