Physics, 28.02.2020 19:42 bhale2030

In a system with two objects interacting via the force of gravity, if the total energy (gravitational binding energy kinetic energy) is zero, then the possible orbits of one object about the other could be .

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Answer from: sarbjit879

Gravitational binding energy is the minimum energy that must be added in the system for it to cease.

Explanation:

A gravitational binding energy is the base vitality that must be added to a framework for the framework to stop being in a gravitationally bound state. A gravitationally bound framework has a lower (i.e., increasingly negative) gravitational potential vitality than the total of its parts—this is the thing that keeps the framework accumulated as per the base all out potential vitality standard.

As indicated by the virial hypothesis, the gravitational binding energy of a star is around multiple times its interior warm vitality all together for hydro static harmony to be maintained. As the gas in a star turns out to be increasingly relativistic, the gravitational restricting vitality required for hydro static balance approaches zero and the star gets insecure (exceptionally delicate to annoyances), which may prompt a supernova in high-mass stars because of solid radiation weight or dark gaps in neutron stars.

Answer from: Quest

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

$_a^z\textrm{x}\rightarrow _{a-2}^{z-4}+_2^4\alpha$

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

$_a^z\textrm{x}+_{-1}^0\textrm{e}\rightarrow _{z-1}^a\textrm{y}$

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases $\gamma -radiations$ . this process does not change the mass number.

$_a^z\textrm{x}^*\rightarrow _a^z\textrm{x}+_0^0\gamma$

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as $\beta ^+$ -decay. in this the mass number remains same.

$_a^z\textrm{x}\rightarrow _{z-1}^a\textrm{y}+_{+1}^0e$

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

Answer from: Quest

the answer is 3.1 his answer is wrong mines is right

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In a system with two objects interacting via the force of gravity, if the total energy (gravitationa...

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