A 10.0 L balloon contains helium gas at a pressure of 660 mmHg . What is the final pressure, in millimeters of mercury, of the helium gas at each of the following volumes, if there is no change in temperature and amount of gas?

(a)= 264mmHg

(b)= 2000mmHg

(c)474.82mmHg

(d)= 511.63mmHg

Explanation:

the question deals with boyles law, which states that the volume of a given mass of gas at constant temperature is inversely proportional to its pressure

V ∝ 1/P

P₁V₁ = P₂V₂

making V₂ as the subject of formular

P₂ = P₁V₁/ V₂

with a volume of  25.0L

P₂ = 660×10 / 25

= 264mmHg

with a volume of 3.30 L

P₂  = 660 × 10 / 3.30

= 2000mmHg

with a volume of 13900 mL

= 13.9L

P₂  =660× 10 / 13.9

474.82mmHg

with a volume of 12900 mL

P₂ =660×10 / 12.9

= 511.63mmHg

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.

the right answer is 0.3 meters per second