A satellite orbiting in a circular orbit with a radius of 66000 m and a speed of 810 m/s, fires a rocket that provides an acceleration of 25 m/s/s. At the instant the rocket fires, what are the magnitude and direction of the total acceleration

The magnitude and direction of the total acceleration is 34.941m/s² upward

Explanation:

The centripetal acceleration due to the circular motion, is calculated as follows;

where;

a is the centripetal acceleration

v is the speed of the satellite =  810 m/s

r is the radius of the circular orbit = 66000 m

Upward acceleration = 25m/s²

Total acceleration = (9.941 + 25)m/s² = 34.941m/s² upward

Therefore, the magnitude and direction of the total acceleration is 34.941m/s² upward