A high-speed sander has a disk of radius 4.71 cm that rotates about its axis at a constant rate of 1547 rev/min. Determine the angular speed of the disk. Answer in units of rad/s.

ω = angular speed = 25 radian per sec

Explanation:

As we know that:

1547 revolution = 1 minute:    1547/60 = 26

26 revolution per sec.

 r= radius = 4.71 cm

    Angular speed = Revolution (Ф) / time taken

                            =  1547 / 60

                              =  25 radian / sec

81.01rad/s

Explanation:

From the question, we are given the radius r = 4.71cm

The rate of rotation ∆θ= 1547rev/min

The angular speed w = ∆θ/∆t

In circular motion, angular speed is the time rate with which the angular displacement occurs. It is also referred to as the rotational speed.

Firstly we need to convert the the 1547rev/min to rad/s

w = 1547× 2π/60

w = 4860.674/60

w=81.01rad/s

it is very well related to a lot of things but with my limited knowledge i can confidently say that the answer is space.

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.