A load of 36 N attached to a spring hanging
vertically stretches the spring 6.5 cm. The
spring is now placed horizontally on a table
and stretched 10 cm.
What force is required to stretch it by this
amount?
Answer in units of N.

The required force is 55.38 N.

Explanation:

First we have to find the spring constant K;

                         k = = = 553.846 N/m

As,

                         F= -K

                   or, F=  - 553.846 × 0.10

                   or, F=  -55.3846 N

Hence,

                  = -

            ∴   = 55.38 N

The required force  to stretch it by this  amount is 55.38 N.  

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach