If the length of a building is 2 1 2 times the width and each dimension is increased by 7 ft, then the perimeter is 266 ft. Find the dimensions of the original building in ft.

The original dimensions of the building is 95 ft × 38 ft.

Explanation:

Let the original length be 'l' and original width be 'w'.

Given:

Original length (l) =

Original width = 'w'.

So,

Now, as per question:

Length and width is increased by 7 ft.

So, new length (l') =

New width (w') =

New perimeter (P) = 266 ft

Perimeter is given as:

Therefore, original width = 38 ft.

Original length is,

Hence, the original dimensions of the building is 95 ft × 38 ft.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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