Physics, 03.03.2020 01:42 YoVeoAnime

A 0.311 kg tennis racket moving
30.3 m/s east makes an elastic
collision with a 0.0570 kg ball
moving 19.2 m/s east. Find the
velocity of the tennis racket after
the collision.

Answers: 1

Show answers

Answers

Answer from: zacharysharpe2805

The velocity of the tennis racket after collision is 26.862 m/s.

Explanation:

If the tennis racket and ball is collided in elastic collision then the sum of momentum before collision will be equal to the sum of momentum after collision. This is in accordance to the law of conservation of energy. So if we consider the mass of tennis racket as m1 = 0.311 kg and the velocity of tennis racket before collision as u1 = 30.3 m/s. Then the mass of the ball is considered as m2 = 0.0570 kg and the velocity of the ball before collision as u2 = 19.2 m/s.

So as per the conservation of energy, the velocity of tennis racket and ball after collision will be denoted as v1 and v2 respectively. The formulas for determining these velocities are

$v_{1} = \frac{m_{1}- m_{2} }{m_{1} + m_{2} } u_{1}+ \frac{ 2*m_{2} }{m_{1} + m_{2} } u_{2}$

$v_{2} = \frac{2*m_{1} }{m_{1} + m_{2} } u_{1}+ \frac{ m_{2}- m_{1} }{m_{1} + m_{2} } u_{2}$

Since, we require to determine only the velocity of tennis racket after collision, so solving the v1 equation is enough with the parameters m1 = 0.311 kg , m2 = 0.0570 kg, u1 = 30.3 m/s and u2 = 19.2 m/s given

$v_{1} = \frac{0.311- 0.0570 }{0.311 + 0.0570 } * 30.3+ \frac{ 2*0.0570 }{0.311 + 0.0570 }*19.2$

$v_{1} = \frac{0.254 }{0.368} * 30.3+ \frac{ 0.114 }{0.368}*19.2$

$v_{1} =20.914+5.948=26.862 m/s$

So, the velocity of the tennis racket after collision is 26.862 m/s.

Answer from: Quest

i think its

Answer from: Quest

1.the balanced chemical equation is as below

cu + 2 ag(no)₃ → cu(no₃)₂ +2 ag

2.the much silver produced is 50.9 g

step 1: find the moles of cu

moles = mass÷ molar mass

from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236 moles

step 2: use the mole ratio to determine the moles of ag

from equation above cu: ag is 1: 2

therefore the moles of ag =0.236 moles x 2/1 =0.472 moles

step 3: find the mass of ag

mass = moles x molar mass

from periodic table the molar mass of ag =107.87 g/mol

mass = 0.472 moles x 107.87 g/mol = 50.9 g

3. the much silver collected worth is 1.797 oz

convert 50.9 g to oz

that is 1 gram = 0.0353 oz

50.9 grams =? oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1 gram} =1.797 oz

Another question on Physics

Physics, 22.06.2019 03:00

Ahot-air balloonist, rising vertically with a constant speed of 5.00 m/s releases a sandbag at the instant the balloon is 40.0 m above the ground. after it is released, the sandbag encounters no appreciable air drag. compute the velocity of the sandbag at 0.250 s after its release.

Answers: 2

Answer

Physics, 22.06.2019 11:00

How do we measure or think of speed in the united states?

Answers: 1

Answer

Physics, 22.06.2019 11:10

Avolcano erupts next to a grassland area in a valley. a. describe three ways in which material released by the volcano could impact the grassland area. b. describe three ways in which the grassland ecosystem could recover after a volcanic eruption.

Answers: 3

Answer

Physics, 22.06.2019 13:00

What causes the formation of ocean currents?

Answers: 1

Answer

You know the right answer?

A 0.311 kg tennis racket moving
30.3 m/s east makes an elastic
collision with a 0.0570 k...

Questions

Physics, 25.07.2019 07:00

In transverse waves, the medium moves perpendicular to the direction of energy transport. true false...

Physics, 25.07.2019 07:00