The area of each plate of a parallel plate capacitor is 0.021 m2. The plates are 2.75 mm apart with a dielectric material (κ = 3.0) between them. The maximum possible electric field between the plates is 3.25 ✕ 105 V/m. What is the maximum energy that can be stored in the capacitor?

Explanation:

The given data is as follows.

        Dielectric constant, K = 3.0

   Area of the plates (A) = 0.021

   Distance between plates (d) =

  Maximum electric field (E) =

Now, we will calculate the capacitance as follows.

             C =

                 =

                 =

                 = F

Formula to calculate electric charge is as follows.

               E =

or,           Q =      (as )

                   =

                   =

Formula to calculate the energy is as follows.

                  U =

                     =

                     =

                     =

or,                  =

Thus, we can conclude that the maximum energy that can be stored in the capacitor is .

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong