L10) Consider two parallel plate capacitors each with area 1 cm2 and separation 1 mm. These capacitors are placed in series under a power source giving 120 V. What is the energy stored on each capacitor?

Explanation:

Formula for the capacitance of a parallel plate capacitor is as follows.

           C =

where,   A = area = 1 =

              d = diameter = 1 mm =

Hence, putting the given values into the above formula as follows.

              C =

                  =

                  =

Now, we will calculate the energy stored in the capacitor as follows.

       U =

           =

           =

or,        =

Thus, we can conclude that energy stored on each capacitor is .

i think it'll be 7,000

no sign of dia of fuel cell