.A particle moving with a constant acceleration has a velocity of 20 cm/s when its position is x = 10 cm. Its position 7.0 s later is x = –30 cm. What is the acceleration of the particle?

Explanation:

The second equation of a uniformly accelerated motion could be used to solve this problem. This is given by equation (1);

where u is the particle's initial velocity, t is the time taken, a is the acceleration and s is the distance travelled.

Given;

u = 20cm/s

t = 7s

a = ?

s = ?

The particle moved from one point to another point along the x-axis, where and . This information could be used to find the distance s covered by the object as follows;

We the make appropriate substitutions into equation (1) and then solve for the acceleration.

The negative sign is an indication that the particle is decelerating.

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

heats surface water up