A 7.35 H inductor with negligible resistance is placed in series with a 14.1 V battery, a 3.00 ? resistor, and a switch. The switch is closed at time t = 0 seconds.

(a) Calculate the initial current at t = 0 seconds.

(b) Calculate the current as time approaches infinity.

(c) Calculate the current at a time of 6.25 s.

(d) Determine how long it takes for the current to reach half of its maximum.

(a). The initial current at t=0 is zero.

(b). The current as time approaches infinity is 4.7 A

(c). The current at a time of 6.25 s is 4.33 A.

(d). The time is 1.69 sec.

Explanation:

Given that,

Inductance = 7.35 H

Voltage = 14.1 V

Resistance= 3.00 ohm

(a). We need to calculate the initial current at t = 0

Using formula of current

Put the value into the formula

(b). We need to calculate the current as time approaches infinity.

Using formula of current

Put the value into the formula

(c).  We need to calculate the current at a time of 6.25 s

Using formula of current

Put the value into the formula

(d). We need to calculate the time

Using  formula of current

Put the value into the formula

Hence, (a). The initial current at t=0 is zero.

(b). The current as time approaches infinity is 4.7 A

(c). The current at a time of 6.25 s is 4.33 A.

(d). The time is 1.69 sec.

terd muffin is the correct answer