A small space telescope at the end of a tether line of length L moves at linear speed v about a central space station. What will be the linear speed of the telescope if the length of the line is changed to x*L ? x = 2.8; v = 2 m/s?

The answer to the question is

The linear speed of the telescope will be 5.6 m/s if the length of the line is changed to x*L where  x = 2.8; and initial velocity v = 2 m/s

Explanation:

Speed = v₁ = ωL = 2 m/s

When the line is changed to x*L where x = 2.8 the linear speed will be

v₂ = 2.8 × L× ω = 2.8× 2 = 5.6 m/s

The linear speed varies with the angular speed following the relation v/r =ω where

ω = angular speed

v = linear speed and

r = radius of the path of travel of the object at the vertex

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: