A steel bucket contains 4 liters of water at 128C. An electric immersion heater rated at 1400 Watts is placed in the * Indicates an advanced level in solving. Problems 61 62 CHAPTER 1 Introduction bucket. Determine how long it will take for water to heat to 708C. Assume that the empty bucket weighs 1.1 kg. The specific heat of steel is 0.46 kJ/(kg 8C). Use an average specific heat of water of 4.18 kJ/(kg 8C). Disregard any heat loss to the surroundings.

The time is 0.713 sec.

Explanation:

Given that,

Weight of water = 4 liters

Initial temperature = 128°C

Power = 1400 Watts

Final temperature = 708°C

Weight = 1.1 kg

Specific heat of steel = 0.46 kJ/kg°C

Specific heat of water = 4.18 kJ/kg°C

We need to calculate the heat gained by bucket

Using formula of heat

Put the value into the formula

We need to calculate the heat gained by water

Using formula of heat

Put the value into the formula

We need to calculate the total heat

Using formula of heat

Put the value into the formula

We need to calculate the time

Using formula of time

Put the value into the formula

Hence, The time is 0.713 sec.