An object of mass 0.77 kg is initially at rest. When a force acts on it for 2.9 ms it acquires a speed of 16.2 m/s. Find the magnitude (in N) of the average force acting on the object during the 2.9 ms time interval. (Enter a number.)

4.3KN

Explanation:f=m(v-u)/t

m=0.77kg

t=0.0029s

s=16.2m/s

F= 0.77*16.2/0.0029

F=12.474/0.0029

F= 4301.38N

F=4.3KN

this is an example of "committed" time.

committed time, as contracted time, takes need over essential and available time since it is seen as profitable work. it alludes to the time allotted to keep up a home and family. at the point when a man is commuting using committed time this individual may feel that the drive is an obligation to family, for example, strolling youngsters to class or driving a mate to work. contracted and committed time clients may feel that their commute could really compare to the commute of important or leisure time clients on the grounds that their commute is profitable work. in this manner, they might be more disposed to pick a mechanized method of movement.  

total distance/total time

(85 + 82)/(5+3)

167/8

20 just over