A baseball (m = 145 g) traveling 32 m/s moves a fielder's glove backward 25 cm when the ball is caught. What was the average force exerted by the ball on the glove?

The average force exerted by the ball on the glove when it was caught is 297 N.

The given parameters:

The acceleration of the baseball is calculated as follows

The average force exerted by the ball on the glove when it was caught is calculated as follows:

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297 N

Explanation:

First, find the acceleration of the ball.

Given:

Δx = 0.25 m

v₀ = 32 m/s

v = 0 m/s

Find: a

v² = v₀² + 2aΔx

(0 m/s)² = (32 m/s)² + 2a (0.25 m)

a = -2048 m/s²

Find the force exerted on the ball by the glove.

F = ma

F = (0.145 kg) (-2048 m/s²)

F = -297 N

The force exerted by the ball on the glove is equal and opposite.

-F = 297 N

Round as needed.

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