A 2 kg object is subjected to two forces, F with arrow1 = 2 N î - 1 N ĵ and F with arrow2 = 18 N î - 9 N ĵ. The object is at rest at the origin at time t = 0. (a) What is the object's acceleration? m/s2 î + m/s2 ĵ> (b) What is its velocity at time t = 12 s? m/s î + m/s ĵ (c) Where is the object at time t = 12 s? m î + m ĵ

A. 10 m/s² i - 5 m/s² j

B. 120 m/s i - 60 m/s j

C. 1440 m i - 720 m j

Explanation:

First, the vector sum of the forces:

F = 2N i - 1N j + 18N i - 9N j

F = 20N i - 10N j

A. Acceleration is given as

a = F/m

Where m = mass = 2 kg

a = (20N i - 10N j)/2

a = 10m/s² i - 5m/s² j

B. Velocity, v = a * t

When t = 12s

v = (10m/s² i - 5m/s² j) * 12

v = 120m/s i - 60 m/s j

C. Distance, d = v * t

d = (120m/s i - 60 m/s j) * 12

d = 1400m i - 720m j

vapour or gas assuming atmospheriv pressure