A transverse wave is set up in a very long string. The oscillator is set at 20.0 Hz, and the wave speed is 78 m/s. The amplitude of the wave is 5.2 cm. What is the maximum particle acceleration for a point on the string?

To solve this problem we must apply the concepts related to Tangential Acceleration based on angular velocity and acceleration, and therefore, we must also calculate angular velocity based on the given frequency. For all these problems we will take the Units to the International System. The maximum acceleration would then be defined as,

Here,

= Angular velocity

A = Amplitude

At the same time the angular velocity is described as,

Here f means the frequency of the wave. Substituting,

Replacing at the first equation,

Therefore the maximum particle acceleration for a point on the string is

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

according to jean piaget, in what stage of cognitive development are children able to understand conservation task?

b. preoperational

just took it