A distance/time graph is drawn to represent a trip John took by car to Edmonton. The time is given in hours and the distance in kilometers. Two points on the graph are (2, 50) and (5, 320). What was John's average velocity between these points?
Select one:
a. 80 km/h
b. 90 km/h
c. 100 km/h
d. 110 km/h

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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