Two parallel plates that are initially uncharged are separated by 1.2 mm. What charge must be transferred from one plate to the other if 11.0 KJ of energy are to be stored in the plates, if area of each plate is 19.0 mm

Explanation:

We start by writing the formula of the energy stored between two charged parallel plates, which is:

Where Q is the charge on one of the plates and C its capacitance, which for two parallel plates is:

Where A is the area of each plate, d the distance between them and the permittivity of the medium, in our case the vacuum, .

Putting all together:

Which means:

Which for our values is:

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards