How do you do this question?

Explanation:

The total surface area is:

A = 2πr² + 2πrL

A = 2π (3.3 cm)² + 2π (3.3 cm) (12 cm)

A = 317.24 cm²

If ρ is the mass per area density in g/cm², then:

m = ρA

50 g = ρ (317.24 cm²)

ρ = 0.158 g/cm²

(a) The mass of the lid is:

m = ρA = ρ πr²

m = (0.158 g/cm²) (π (3.3 cm)²)

m = 5.39 g

(b) The mass of the shell is:

M = ρA = ρ 2πrL

M = (0.158 g/cm²) (2π (3.3 cm) (12 cm))

M = 39.22 g

(c) The moment of inertia of the lid/bottom is I = 1/2 mr².

The moment of inertia of the shell is I = Mr².

The total moment of inertia is:

I = 1/2 mr² + Mr² + 1/2 mr²

I = (m + M) r²

I = (5.39 g + 39.22 g) (3.3 cm)²

I = 485.78 g cm²

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m