A 19.0-kg cannonball is fired from a cannon with muzzle speed of 800 m/s at an angle of 33.0° with the horizontal. A second ball is fired with the same initial speed at an angle of 90.0°. Let y = 0 at the cannon. Use the isolated system model to find the maximum height reached by each ball. hfirst ball = .

The maximum height reached by both balls are 9685.93 meters and 32653.06 meters respectively.

Explanation:

Given that,

Mass of the first cannonball,

Initial speed of the first cannonball,

Angle of projection of the first cannonball,

Angle of projection of the second cannonball,

In this case, we need to find the maximum height reached by each ball. We know that the maximum height reached by a projectile is given by :

The maximum height reached by the second ball is given by :

So, the maximum height reached by both balls are 9685.93 meters and 32653.06 meters respectively. Hence, this is the required solution.

(75°f − 32) × 5/9 = 23.889°c

this is an example of "committed" time.

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