A certain metal with atomic mass 2.9 × 10−25 kg has an interatomic bond with length 2.3 × 10−10 m and stiffness 48 N/m. What is the speed of sound in a rod made of this metal?

Speed of sound = 2958.88m/s

Explanation:

The speed of sound is given by:

V = Sqrt(s/m)× d

Where a = stiffness of the metal

m = atomic mass of the metal

d,= distance

Given:

s= 48N/m

d= 2.3×10^-10m

m = 2.9×10^-25kg

V = Sqrt(48/(2.9×10^-25) × 2.3× 10^-10

V = Sqrt(1.655×10^26)×2.3×10^-10

V = 1.286×10^13 × 2.3×10^-10

V = 2958.88m/s

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)